11401350313 has 4 divisors (see below), whose sum is σ = 11557533268. Its totient is φ = 11245167360.

The previous prime is 11401350293. The next prime is 11401350371. The reversal of 11401350313 is 31305310411.

11401350313 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8443404544 + 2957945769 = 91888^2 + 54387^2 .

It is a cyclic number.

It is not a de Polignac number, because 11401350313 - 2³³ = 2811415721 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11401350383) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 78091368 + ... + 78091513.

It is an arithmetic number, because the mean of its divisors is an integer number (2889383317).

Almost surely, 2^11401350313 is an apocalyptic number.

It is an amenable number.

11401350313 is a deficient number, since it is larger than the sum of its proper divisors (156182955).

11401350313 is an equidigital number, since it uses as much as digits as its factorization.

11401350313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 156182954.

The product of its (nonzero) digits is 540, while the sum is 22.

Adding to 11401350313 its reverse (31305310411), we get a palindrome (42706660724).

The spelling of 11401350313 in words is "eleven billion, four hundred one million, three hundred fifty thousand, three hundred thirteen".