11402222112131 has 4 divisors (see below), whose sum is σ = 11402231685792. Its totient is φ = 11402212538472.

The previous prime is 11402222112121. The next prime is 11402222112167. The reversal of 11402222112131 is 13121122220411.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 11402222112131 - 2¹⁰ = 11402222111107 is a prime.

It is a super-2 number, since 2×11402222112131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11402222112097 and 11402222112106.

It is not an unprimeable number, because it can be changed into a prime (11402222112121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2695880 + ... + 5483813.

It is an arithmetic number, because the mean of its divisors is an integer number (2850557921448).

Almost surely, 2^{11402222112131} is an apocalyptic number.

11402222112131 is a deficient number, since it is larger than the sum of its proper divisors (9573661).

11402222112131 is an equidigital number, since it uses as much as digits as its factorization.

11402222112131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9573660.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 11402222112131 its reverse (13121122220411), we get a palindrome (24523344332542).

The spelling of 11402222112131 in words is "eleven trillion, four hundred two billion, two hundred twenty-two million, one hundred twelve thousand, one hundred thirty-one".