Base | Representation |
---|---|
bin | 110101000110001010… |
… | …0011010111011101011 |
3 | 101220022110222110102112 |
4 | 1222030110122323223 |
5 | 3332004432010011 |
6 | 124214231152535 |
7 | 11144414112230 |
oct | 1521424327353 |
9 | 356273873375 |
10 | 114023313131 |
11 | 443a2207892 |
12 | 1a12221574b |
13 | a9a1bc1a70 |
14 | 5739685787 |
15 | 2e7542558b |
hex | 1a8c51aeeb |
114023313131 has 16 divisors (see below), whose sum is σ = 142027194624. Its totient is φ = 89129299104.
The previous prime is 114023313077. The next prime is 114023313163. The reversal of 114023313131 is 131313320411.
It is a cyclic number.
It is not a de Polignac number, because 114023313131 - 214 = 114023296747 is a prime.
It is a super-2 number, since 2×1140233131312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 114023313097 and 114023313106.
It is not an unprimeable number, because it can be changed into a prime (114023313191) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7540661 + ... + 7555766.
It is an arithmetic number, because the mean of its divisors is an integer number (8876699664).
Almost surely, 2114023313131 is an apocalyptic number.
114023313131 is a deficient number, since it is larger than the sum of its proper divisors (28003881493).
114023313131 is a wasteful number, since it uses less digits than its factorization.
114023313131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15096530.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 114023313131 its reverse (131313320411), we get a palindrome (245336633542).
The spelling of 114023313131 in words is "one hundred fourteen billion, twenty-three million, three hundred thirteen thousand, one hundred thirty-one".
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