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114023433 = 338007811
BaseRepresentation
bin1101100101111…
…01110000001001
321221112222202010
412302331300021
5213142222213
615151530133
72553116556
oct662756011
9257488663
10114023433
11593aa547
1232229949
131a8137b4
1411201a2d
15a024ac3
hex6cbdc09

114023433 has 4 divisors (see below), whose sum is σ = 152031248. Its totient is φ = 76015620.

The previous prime is 114023383. The next prime is 114023467. The reversal of 114023433 is 334320411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 334320411 = 3111440137.

It is a de Polignac number, because none of the positive numbers 2k-114023433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (114023033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19003903 + ... + 19003908.

It is an arithmetic number, because the mean of its divisors is an integer number (38007812).

Almost surely, 2114023433 is an apocalyptic number.

It is an amenable number.

114023433 is a deficient number, since it is larger than the sum of its proper divisors (38007815).

114023433 is an equidigital number, since it uses as much as digits as its factorization.

114023433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38007814.

The product of its (nonzero) digits is 864, while the sum is 21.

The square root of 114023433 is about 10678.1755464124. The cubic root of 114023433 is about 484.9139791465.

Adding to 114023433 its reverse (334320411), we get a palindrome (448343844).

The spelling of 114023433 in words is "one hundred fourteen million, twenty-three thousand, four hundred thirty-three".

Divisors: 1 3 38007811 114023433