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11403001131 = 336731034849
BaseRepresentation
bin10101001111010101…
…11111110100101011
31002102200202110212020
422213222333310223
5141323132014011
65123301515523
7552401624154
oct124752776453
932380673766
1011403001131
114921773585
122262a12ba3
1310c9579c62
147a261692b
1546b147006
hex2a7abfd2b

11403001131 has 8 divisors (see below), whose sum is σ = 15208155600. Its totient is φ = 7599923712.

The previous prime is 11403001123. The next prime is 11403001133. The reversal of 11403001131 is 13110030411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11403001131 - 23 = 11403001123 is a prime.

It is a super-2 number, since 2×114030011312 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11403001131.

It is not an unprimeable number, because it can be changed into a prime (11403001133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 506406 + ... + 528443.

It is an arithmetic number, because the mean of its divisors is an integer number (1901019450).

Almost surely, 211403001131 is an apocalyptic number.

11403001131 is a deficient number, since it is larger than the sum of its proper divisors (3805154469).

11403001131 is a wasteful number, since it uses less digits than its factorization.

11403001131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1038525.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 11403001131 its reverse (13110030411), we get a palindrome (24513031542).

The spelling of 11403001131 in words is "eleven billion, four hundred three million, one thousand, one hundred thirty-one".

Divisors: 1 3 3673 11019 1034849 3104547 3801000377 11403001131