114032012131 has 8 divisors (see below), whose sum is σ = 120037227200. Its totient is φ = 108027150120.

The previous prime is 114032012099. The next prime is 114032012183. The reversal of 114032012131 is 131210230411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 114032012131 - 2⁵ = 114032012099 is a prime.

It is a super-2 number, since 2×114032012131² (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (19).

It is a junction number, because it is equal to n+sod(n) for n = 114032012099 and 114032012108.

It is not an unprimeable number, because it can be changed into a prime (114032013131) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 808336 + ... + 938866.

It is an arithmetic number, because the mean of its divisors is an integer number (15004653400).

Almost surely, 2^114032012131 is an apocalyptic number.

114032012131 is a deficient number, since it is larger than the sum of its proper divisors (6005215069).

114032012131 is a wasteful number, since it uses less digits than its factorization.

114032012131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 176529.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 114032012131 its reverse (131210230411), we get a palindrome (245242242542).

The spelling of 114032012131 in words is "one hundred fourteen billion, thirty-two million, twelve thousand, one hundred thirty-one".