1140323035 has 4 divisors (see below), whose sum is σ = 1368387648. Its totient is φ = 912258424.

The previous prime is 1140323033. The next prime is 1140323053. The reversal of 1140323035 is 5303230411.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 5303230411 = 397 ⋅13358263.

It is a cyclic number.

It is not a de Polignac number, because 1140323035 - 2¹ = 1140323033 is a prime.

It is a super-4 number, since 4×1140323035⁴ (a number of 37 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1140322997 and 1140323015.

It is not an unprimeable number, because it can be changed into a prime (1140323033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 114032299 + ... + 114032308.

It is an arithmetic number, because the mean of its divisors is an integer number (342096912).

Almost surely, 2^1140323035 is an apocalyptic number.

1140323035 is a deficient number, since it is larger than the sum of its proper divisors (228064613).

1140323035 is an equidigital number, since it uses as much as digits as its factorization.

1140323035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 228064612.

The product of its (nonzero) digits is 1080, while the sum is 22.

The square root of 1140323035 is about 33768.6694289248. The cubic root of 1140323035 is about 1044.7425890099.

Adding to 1140323035 its reverse (5303230411), we get a palindrome (6443553446).

The spelling of 1140323035 in words is "one billion, one hundred forty million, three hundred twenty-three thousand, thirty-five".