Base | Representation |
---|---|
bin | 10101001111010111… |
… | …11010111100111011 |
3 | 1002102201012210002022 |
4 | 22213223322330323 |
5 | 141323212241243 |
6 | 5123311025055 |
7 | 552403653233 |
oct | 124753727473 |
9 | 32381183068 |
10 | 11403243323 |
11 | 492191953a |
12 | 2262b0b18b |
13 | 10c9633274 |
14 | 7a267acc3 |
15 | 46b193b68 |
hex | 2a7afaf3b |
11403243323 has 16 divisors (see below), whose sum is σ = 12504456000. Its totient is φ = 10350692352.
The previous prime is 11403243283. The next prime is 11403243337. The reversal of 11403243323 is 32334230411.
It is not a de Polignac number, because 11403243323 - 210 = 11403242299 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11403243292 and 11403243301.
It is not an unprimeable number, because it can be changed into a prime (11403243343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 440483 + ... + 465651.
It is an arithmetic number, because the mean of its divisors is an integer number (781528500).
Almost surely, 211403243323 is an apocalyptic number.
11403243323 is a deficient number, since it is larger than the sum of its proper divisors (1101212677).
11403243323 is a wasteful number, since it uses less digits than its factorization.
11403243323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26134.
The product of its (nonzero) digits is 5184, while the sum is 26.
Adding to 11403243323 its reverse (32334230411), we get a palindrome (43737473734).
The spelling of 11403243323 in words is "eleven billion, four hundred three million, two hundred forty-three thousand, three hundred twenty-three".
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