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1140325555 = 5228065111
BaseRepresentation
bin100001111110111…
…1111110010110011
32221110201112120211
41003331333302303
54313410404210
6305053044551
740154415205
oct10375776263
92843645524
101140325555
11535758516
12279a86757
1315232c765
14ab638775
156a19e38a
hex43f7fcb3

1140325555 has 4 divisors (see below), whose sum is σ = 1368390672. Its totient is φ = 912260440.

The previous prime is 1140325553. The next prime is 1140325561. The reversal of 1140325555 is 5555230411.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1140325555 - 21 = 1140325553 is a prime.

It is a Smith number, since the sum of its digits (31) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1140325553) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 114032551 + ... + 114032560.

It is an arithmetic number, because the mean of its divisors is an integer number (342097668).

Almost surely, 21140325555 is an apocalyptic number.

1140325555 is a deficient number, since it is larger than the sum of its proper divisors (228065117).

1140325555 is an equidigital number, since it uses as much as digits as its factorization.

1140325555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 228065116.

The product of its (nonzero) digits is 15000, while the sum is 31.

The square root of 1140325555 is about 33768.7067415973. The cubic root of 1140325555 is about 1044.7433586016.

Adding to 1140325555 its reverse (5555230411), we get a palindrome (6695555966).

The spelling of 1140325555 in words is "one billion, one hundred forty million, three hundred twenty-five thousand, five hundred fifty-five".

Divisors: 1 5 228065111 1140325555