11403324444001 has 4 divisors (see below), whose sum is σ = 13032370793152. Its totient is φ = 9774278094852.

The previous prime is 11403324443947. The next prime is 11403324444023. The reversal of 11403324444001 is 10044442330411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11403324444001 - 2¹⁵ = 11403324411233 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11403324442001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 814523174565 + ... + 814523174578.

It is an arithmetic number, because the mean of its divisors is an integer number (3258092698288).

Almost surely, 2^{11403324444001} is an apocalyptic number.

It is an amenable number.

11403324444001 is a deficient number, since it is larger than the sum of its proper divisors (1629046349151).

11403324444001 is an equidigital number, since it uses as much as digits as its factorization.

11403324444001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1629046349150.

The product of its (nonzero) digits is 18432, while the sum is 31.

Adding to 11403324444001 its reverse (10044442330411), we get a palindrome (21447766774412).

The spelling of 11403324444001 in words is "eleven trillion, four hundred three billion, three hundred twenty-four million, four hundred forty-four thousand, one".