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11403400153 = 73156210961
BaseRepresentation
bin10101001111011001…
…00001001111011001
31002102201111202012211
422213230201033121
5141323232301103
65123314235121
7552405205405
oct124754411731
932381452184
1011403400153
114921a16352
122262b85aa1
1310c9689772
147a26bc105
1546b1c536d
hex2a7b213d9

11403400153 has 4 divisors (see below), whose sum is σ = 11559611188. Its totient is φ = 11247189120.

The previous prime is 11403400091. The next prime is 11403400157. The reversal of 11403400153 is 35100430411.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 9578145424 + 1825254729 = 97868^2 + 42723^2 .

It is a cyclic number.

It is not a de Polignac number, because 11403400153 - 217 = 11403269081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11403400157) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 78105408 + ... + 78105553.

It is an arithmetic number, because the mean of its divisors is an integer number (2889902797).

Almost surely, 211403400153 is an apocalyptic number.

It is an amenable number.

11403400153 is a deficient number, since it is larger than the sum of its proper divisors (156211035).

11403400153 is an equidigital number, since it uses as much as digits as its factorization.

11403400153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 156211034.

The product of its (nonzero) digits is 720, while the sum is 22.

Adding to 11403400153 its reverse (35100430411), we get a palindrome (46503830564).

The spelling of 11403400153 in words is "eleven billion, four hundred three million, four hundred thousand, one hundred fifty-three".

Divisors: 1 73 156210961 11403400153