Base | Representation |
---|---|
bin | 10101001111011001… |
… | …00110111011001001 |
3 | 1002102201112221011001 |
4 | 22213230212323021 |
5 | 141323234022213 |
6 | 5123314535001 |
7 | 552405333313 |
oct | 124754467311 |
9 | 32381487131 |
10 | 11403423433 |
11 | 4921a31896 |
12 | 2262b97461 |
13 | 10c969723c |
14 | 7a26c67b3 |
15 | 46b1cc1dd |
hex | 2a7b26ec9 |
11403423433 has 4 divisors (see below), whose sum is σ = 11407676368. Its totient is φ = 11399170500.
The previous prime is 11403423403. The next prime is 11403423467. The reversal of 11403423433 is 33432430411.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11403423433 - 213 = 11403415241 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11403423403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2122443 + ... + 2127808.
It is an arithmetic number, because the mean of its divisors is an integer number (2851919092).
Almost surely, 211403423433 is an apocalyptic number.
It is an amenable number.
11403423433 is a deficient number, since it is larger than the sum of its proper divisors (4252935).
11403423433 is an equidigital number, since it uses as much as digits as its factorization.
11403423433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4252934.
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 11403423433 its reverse (33432430411), we get a palindrome (44835853844).
The spelling of 11403423433 in words is "eleven billion, four hundred three million, four hundred twenty-three thousand, four hundred thirty-three".
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