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114040241153 = 156772776159
BaseRepresentation
bin110101000110101010…
…0111111110000000001
3101220100122211111022022
41222031110333300001
53332023300204103
6124220034051225
711145011025116
oct1521524776001
9356318744268
10114040241153
114440081a093
121a127a19b15
13a9a556ab47
14573ba1090d
152e76b6b138
hex1a8d53fc01

114040241153 has 4 divisors (see below), whose sum is σ = 114113018880. Its totient is φ = 113967463428.

The previous prime is 114040241149. The next prime is 114040241209. The reversal of 114040241153 is 351142040411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 114040241153 - 22 = 114040241149 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (114040201153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36386513 + ... + 36389646.

It is an arithmetic number, because the mean of its divisors is an integer number (28528254720).

Almost surely, 2114040241153 is an apocalyptic number.

It is an amenable number.

114040241153 is a deficient number, since it is larger than the sum of its proper divisors (72777727).

114040241153 is an equidigital number, since it uses as much as digits as its factorization.

114040241153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 72777726.

The product of its (nonzero) digits is 1920, while the sum is 26.

Adding to 114040241153 its reverse (351142040411), we get a palindrome (465182281564).

The spelling of 114040241153 in words is "one hundred fourteen billion, forty million, two hundred forty-one thousand, one hundred fifty-three".

Divisors: 1 1567 72776159 114040241153