114050403304353 has 6 divisors (see below), whose sum is σ = 164739471439634. Its totient is φ = 76033602202896.

The previous prime is 114050403304351. The next prime is 114050403304361. The reversal of 114050403304353 is 353403304050411.

114050403304353 is a `hidden beast` number, since 1 + 140 + 50 + 4 + 0 + 3 + 30 + 435 + 3 = 666.

It can be written as a sum of positive squares in only one way, i.e., 113605391567889 + 445011736464 = 10658583^2 + 667092^2 .

It is not a de Polignac number, because 114050403304353 - 2¹ = 114050403304351 is a prime.

It is a super-2 number, since 2×114050403304353² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (114050403304351) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 6336133516900 + ... + 6336133516917.

Almost surely, 2^{114050403304353} is an apocalyptic number.

It is an amenable number.

114050403304353 is a deficient number, since it is larger than the sum of its proper divisors (50689068135281).

114050403304353 is a wasteful number, since it uses less digits than its factorization.

114050403304353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12672267033823 (or 12672267033820 counting only the distinct ones).

The product of its (nonzero) digits is 129600, while the sum is 36.

Adding to 114050403304353 its reverse (353403304050411), we get a palindrome (467453707354764).

The spelling of 114050403304353 in words is "one hundred fourteen trillion, fifty billion, four hundred three million, three hundred four thousand, three hundred fifty-three".