114054420433 has 4 divisors (see below), whose sum is σ = 115616809828. Its totient is φ = 112492031040.

The previous prime is 114054420413. The next prime is 114054420437. The reversal of 114054420433 is 334024450411.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 334024450411 = 17 ⋅19648497083.

It can be written as a sum of positive squares in 2 ways, for example, as 55183647744 + 58870772689 = 234912^2 + 242633^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-114054420433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114054420395 and 114054420404.

It is not an unprimeable number, because it can be changed into a prime (114054420437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 781194588 + ... + 781194733.

It is an arithmetic number, because the mean of its divisors is an integer number (28904202457).

Almost surely, 2^114054420433 is an apocalyptic number.

It is an amenable number.

114054420433 is a deficient number, since it is larger than the sum of its proper divisors (1562389395).

114054420433 is an equidigital number, since it uses as much as digits as its factorization.

114054420433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1562389394.

The product of its (nonzero) digits is 23040, while the sum is 31.

Adding to 114054420433 its reverse (334024450411), we get a palindrome (448078870844).

The spelling of 114054420433 in words is "one hundred fourteen billion, fifty-four million, four hundred twenty thousand, four hundred thirty-three".