Base | Representation |
---|---|
bin | 110101000111011001… |
… | …0010011111111001001 |
3 | 101220102100212022020200 |
4 | 1222032302103333021 |
5 | 3332101031002213 |
6 | 124222310242413 |
7 | 11145425660532 |
oct | 1521662237711 |
9 | 356370768220 |
10 | 114064703433 |
11 | 44413607a4a |
12 | 1a134056409 |
13 | a9aa654375 |
14 | 5740d7b689 |
15 | 2e78d9e273 |
hex | 1a8ec93fc9 |
114064703433 has 6 divisors (see below), whose sum is σ = 164760127194. Its totient is φ = 76043135616.
The previous prime is 114064703411. The next prime is 114064703447. The reversal of 114064703433 is 334307460411.
114064703433 is a `hidden beast` number, since 1 + 1 + 4 + 0 + 647 + 0 + 3 + 4 + 3 + 3 = 666.
It can be written as a sum of positive squares in only one way, i.e., 90764817984 + 23299885449 = 301272^2 + 152643^2 .
It is not a de Polignac number, because 114064703433 - 28 = 114064703177 is a prime.
It is not an unprimeable number, because it can be changed into a prime (114064703033) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 6336927960 + ... + 6336927977.
It is an arithmetic number, because the mean of its divisors is an integer number (27460021199).
Almost surely, 2114064703433 is an apocalyptic number.
It is an amenable number.
114064703433 is a deficient number, since it is larger than the sum of its proper divisors (50695423761).
114064703433 is a wasteful number, since it uses less digits than its factorization.
114064703433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12673855943 (or 12673855940 counting only the distinct ones).
The product of its (nonzero) digits is 72576, while the sum is 36.
The spelling of 114064703433 in words is "one hundred fourteen billion, sixty-four million, seven hundred three thousand, four hundred thirty-three".
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