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11410002221403 = 317367609606359
BaseRepresentation
bin1010011000001001100100…
…1000010001100101011011
31111101210012200011112121210
42212002121020101211123
52443420141032041103
640133403242034203
72255226330440562
oct246023110214533
944353180145553
1011410002221403
1136a9a55883295
1213434027a8963
13649c600499a6
142b6365cb8bd9
1514bc0124de03
hexa609921195b

11410002221403 has 16 divisors (see below), whose sum is σ = 16152130114560. Its totient is φ = 7139709664896.

The previous prime is 11410002221399. The next prime is 11410002221549. The reversal of 11410002221403 is 30412220001411.

It is not a de Polignac number, because 11410002221403 - 22 = 11410002221399 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11410002221403.

It is not an unprimeable number, because it can be changed into a prime (11410002221203) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 304784463 + ... + 304821896.

It is an arithmetic number, because the mean of its divisors is an integer number (1009508132160).

Almost surely, 211410002221403 is an apocalyptic number.

11410002221403 is a deficient number, since it is larger than the sum of its proper divisors (4742127893157).

11410002221403 is a wasteful number, since it uses less digits than its factorization.

11410002221403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 609606746.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 11410002221403 its reverse (30412220001411), we get a palindrome (41822222222814).

The spelling of 11410002221403 in words is "eleven trillion, four hundred ten billion, two million, two hundred twenty-one thousand, four hundred three".

Divisors: 1 3 17 51 367 1101 6239 18717 609606359 1828819077 10363308103 31089924309 223725533753 671176601259 3803334073801 11410002221403