11410043321 has 4 divisors (see below), whose sum is σ = 11422995444. Its totient is φ = 11397091200.

The previous prime is 11410043317. The next prime is 11410043327. The reversal of 11410043321 is 12334001411.

11410043321 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 12334001411 = 19 ⋅649157969.

It can be written as a sum of positive squares in 2 ways, for example, as 4110733225 + 7299310096 = 64115^2 + 85436^2 .

It is a cyclic number.

It is not a de Polignac number, because 11410043321 - 2² = 11410043317 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11410043293 and 11410043302.

It is not an unprimeable number, because it can be changed into a prime (11410043327) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6474740 + ... + 6476501.

It is an arithmetic number, because the mean of its divisors is an integer number (2855748861).

Almost surely, 2^11410043321 is an apocalyptic number.

It is an amenable number.

11410043321 is a deficient number, since it is larger than the sum of its proper divisors (12952123).

11410043321 is an equidigital number, since it uses as much as digits as its factorization.

11410043321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12952122.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 11410043321 its reverse (12334001411), we get a palindrome (23744044732).

The spelling of 11410043321 in words is "eleven billion, four hundred ten million, forty-three thousand, three hundred twenty-one".