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1141014131 = 2129535939
BaseRepresentation
bin100010000000010…
…0111111001110011
32221112000112010122
41010000213321303
54314044423011
6305115520455
740163313545
oct10400477163
92845015118
101141014131
11536088894
1227a15912b
13152510cba
14ab777695
156a2883db
hex44027e73

1141014131 has 4 divisors (see below), whose sum is σ = 1141552200. Its totient is φ = 1140476064.

The previous prime is 1141014113. The next prime is 1141014139. The reversal of 1141014131 is 1314101411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1141014131 - 218 = 1140751987 is a prime.

It is a super-2 number, since 2×11410141312 = 2603826494283370322, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1141014139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 265841 + ... + 270098.

It is an arithmetic number, because the mean of its divisors is an integer number (285388050).

Almost surely, 21141014131 is an apocalyptic number.

1141014131 is a deficient number, since it is larger than the sum of its proper divisors (538069).

1141014131 is an equidigital number, since it uses as much as digits as its factorization.

1141014131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 538068.

The product of its (nonzero) digits is 48, while the sum is 17.

The square root of 1141014131 is about 33778.9006777900. The cubic root of 1141014131 is about 1044.9536027873.

Adding to 1141014131 its reverse (1314101411), we get a palindrome (2455115542).

The spelling of 1141014131 in words is "one billion, one hundred forty-one million, fourteen thousand, one hundred thirty-one".

Divisors: 1 2129 535939 1141014131