Base | Representation |
---|---|
bin | 10101010000001110… |
… | …11000001110101011 |
3 | 1002110012202110121210 |
4 | 22220013120032223 |
5 | 141332033104011 |
6 | 5124125204203 |
7 | 552522102135 |
oct | 125007301653 |
9 | 32405673553 |
10 | 11410441131 |
11 | 4925995341 |
12 | 2265400663 |
13 | 10cac8351b |
14 | 7a35d2055 |
15 | 46bb166a6 |
hex | 2a81d83ab |
11410441131 has 8 divisors (see below), whose sum is σ = 15214832640. Its totient is φ = 7606505192.
The previous prime is 11410441109. The next prime is 11410441139. The reversal of 11410441131 is 13114401411.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11410441131 - 222 = 11406246827 is a prime.
It is a super-2 number, since 2×114104411312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11410441098 and 11410441107.
It is not an unprimeable number, because it can be changed into a prime (11410441139) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 50391 + ... + 159248.
It is an arithmetic number, because the mean of its divisors is an integer number (1901854080).
Almost surely, 211410441131 is an apocalyptic number.
11410441131 is a deficient number, since it is larger than the sum of its proper divisors (3804391509).
11410441131 is a wasteful number, since it uses less digits than its factorization.
11410441131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 227785.
The product of its (nonzero) digits is 192, while the sum is 21.
Adding to 11410441131 its reverse (13114401411), we get a palindrome (24524842542).
The spelling of 11410441131 in words is "eleven billion, four hundred ten million, four hundred forty-one thousand, one hundred thirty-one".
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