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11411040313 = 1009106310639
BaseRepresentation
bin10101010000010011…
…01010100000111001
31002110020212220112201
422220021222200321
5141332211242223
65124150110201
7552530146051
oct125011524071
932406786481
1011411040313
114926264532
12226564b361
1310cb13317a
147a370a561
1546bbd3ead
hex2a826a839

11411040313 has 8 divisors (see below), whose sum is σ = 11434169600. Its totient is φ = 11387936448.

The previous prime is 11411040307. The next prime is 11411040353. The reversal of 11411040313 is 31304011411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11411040313 - 25 = 11411040281 is a prime.

It is a super-2 number, since 2×114110403132 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11411040353) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1067248 + ... + 1077886.

It is an arithmetic number, because the mean of its divisors is an integer number (1429271200).

Almost surely, 211411040313 is an apocalyptic number.

It is an amenable number.

11411040313 is a deficient number, since it is larger than the sum of its proper divisors (23129287).

11411040313 is a wasteful number, since it uses less digits than its factorization.

11411040313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12711.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 11411040313 its reverse (31304011411), we get a palindrome (42715051724).

The spelling of 11411040313 in words is "eleven billion, four hundred eleven million, forty thousand, three hundred thirteen".

Divisors: 1 1009 1063 10639 1072567 10734751 11309257 11411040313