114112231354001 has 4 divisors (see below), whose sum is σ = 114601983420132. Its totient is φ = 113622479287872.

The previous prime is 114112231353977. The next prime is 114112231354031. The reversal of 114112231354001 is 100453132211411.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 14121211152400 + 99991020201601 = 3757820^2 + 9999551^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-114112231354001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (114112231354031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 244876032716 + ... + 244876033181.

It is an arithmetic number, because the mean of its divisors is an integer number (28650495855033).

Almost surely, 2^{114112231354001} is an apocalyptic number.

It is an amenable number.

114112231354001 is a deficient number, since it is larger than the sum of its proper divisors (489752066131).

114112231354001 is an equidigital number, since it uses as much as digits as its factorization.

114112231354001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 489752066130.

The product of its (nonzero) digits is 2880, while the sum is 29.

Adding to 114112231354001 its reverse (100453132211411), we get a palindrome (214565363565412).

The spelling of 114112231354001 in words is "one hundred fourteen trillion, one hundred twelve billion, two hundred thirty-one million, three hundred fifty-four thousand, one".