114112532137 has 4 divisors (see below), whose sum is σ = 114125151700. Its totient is φ = 114099912576.

The previous prime is 114112532081. The next prime is 114112532159. The reversal of 114112532137 is 731235211411.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 731235211411 = 383 ⋅1909230317.

It can be written as a sum of positive squares in 2 ways, for example, as 90158469696 + 23954062441 = 300264^2 + 154771^2 .

It is a cyclic number.

It is not a de Polignac number, because 114112532137 - 2¹¹ = 114112530089 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114112532099 and 114112532108.

It is not an unprimeable number, because it can be changed into a prime (114112532197) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6296208 + ... + 6314305.

It is an arithmetic number, because the mean of its divisors is an integer number (28531287925).

Almost surely, 2^114112532137 is an apocalyptic number.

It is an amenable number.

114112532137 is a deficient number, since it is larger than the sum of its proper divisors (12619563).

114112532137 is an equidigital number, since it uses as much as digits as its factorization.

114112532137 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12619562.

The product of its digits is 5040, while the sum is 31.

Adding to 114112532137 its reverse (731235211411), we get a palindrome (845347743548).

The spelling of 114112532137 in words is "one hundred fourteen billion, one hundred twelve million, five hundred thirty-two thousand, one hundred thirty-seven".