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114113055235 = 522822611047
BaseRepresentation
bin110101001000110101…
…0110000101000000011
3101220112201211211110011
41222101222300220003
53332200420231420
6124231154445351
711146553652064
oct1522152605003
9356481754404
10114113055235
1144438932413
121a148293857
13a9b76834ba
14574756656b
152e7d25095a
hex1a91ab0a03

114113055235 has 4 divisors (see below), whose sum is σ = 136935666288. Its totient is φ = 91290444184.

The previous prime is 114113055229. The next prime is 114113055247. The reversal of 114113055235 is 532550311411.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 532550311411 = 5021106064591.

It is a cyclic number.

It is not a de Polignac number, because 114113055235 - 23 = 114113055227 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114113055197 and 114113055206.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11411305519 + ... + 11411305528.

It is an arithmetic number, because the mean of its divisors is an integer number (34233916572).

Almost surely, 2114113055235 is an apocalyptic number.

114113055235 is a deficient number, since it is larger than the sum of its proper divisors (22822611053).

114113055235 is an equidigital number, since it uses as much as digits as its factorization.

114113055235 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22822611052.

The product of its (nonzero) digits is 9000, while the sum is 31.

Adding to 114113055235 its reverse (532550311411), we get a palindrome (646663366646).

The spelling of 114113055235 in words is "one hundred fourteen billion, one hundred thirteen million, fifty-five thousand, two hundred thirty-five".

Divisors: 1 5 22822611047 114113055235