11411312131 has 4 divisors (see below), whose sum is σ = 11555759200. Its totient is φ = 11266865064.

The previous prime is 11411312111. The next prime is 11411312141. The reversal of 11411312131 is 13121311411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11411312131 - 2¹¹ = 11411310083 is a prime.

It is a super-3 number, since 3×11411312131³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11411312099 and 11411312108.

It is not an unprimeable number, because it can be changed into a prime (11411312111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 72223416 + ... + 72223573.

It is an arithmetic number, because the mean of its divisors is an integer number (2888939800).

Almost surely, 2^11411312131 is an apocalyptic number.

11411312131 is a deficient number, since it is larger than the sum of its proper divisors (144447069).

11411312131 is an equidigital number, since it uses as much as digits as its factorization.

11411312131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 144447068.

The product of its digits is 72, while the sum is 19.

Adding to 11411312131 its reverse (13121311411), we get a palindrome (24532623542).

The spelling of 11411312131 in words is "eleven billion, four hundred eleven million, three hundred twelve thousand, one hundred thirty-one".