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114114010433 = 1729947244423
BaseRepresentation
bin110101001000110111…
…0011001110101000001
3101220112210122100201212
41222101232121311001
53332201141313213
6124231231135505
711146565040653
oct1522156316501
9356483570655
10114114010433
1144439425035
121a148674595
13a9b79291c7
1457477346d3
152e7d38d9a8
hex1a91b99d41

114114010433 has 16 divisors (see below), whose sum is σ = 125125534080. Its totient is φ = 103587998976.

The previous prime is 114114010421. The next prime is 114114010447. The reversal of 114114010433 is 334010411411.

It is a cyclic number.

It is not a de Polignac number, because 114114010433 - 28 = 114114010177 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114114010399 and 114114010408.

It is not an unprimeable number, because it can be changed into a prime (114114010733) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 344660 + ... + 589082.

It is an arithmetic number, because the mean of its divisors is an integer number (7820345880).

Almost surely, 2114114010433 is an apocalyptic number.

It is an amenable number.

114114010433 is a deficient number, since it is larger than the sum of its proper divisors (11011523647).

114114010433 is a wasteful number, since it uses less digits than its factorization.

114114010433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 245416.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 114114010433 its reverse (334010411411), we get a palindrome (448124421844).

The spelling of 114114010433 in words is "one hundred fourteen billion, one hundred fourteen million, ten thousand, four hundred thirty-three".

Divisors: 1 17 29 493 947 16099 27463 244423 466871 4155191 7088267 120500539 231468581 3934965877 6712588849 114114010433