11411402115 has 8 divisors (see below), whose sum is σ = 18258243408. Its totient is φ = 6086081120.

The previous prime is 11411402113. The next prime is 11411402141. The reversal of 11411402115 is 51120411411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11411402115 - 2¹ = 11411402113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11411402091 and 11411402100.

It is not an unprimeable number, because it can be changed into a prime (11411402113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 380380056 + ... + 380380085.

It is an arithmetic number, because the mean of its divisors is an integer number (2282280426).

Almost surely, 2^11411402115 is an apocalyptic number.

11411402115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

11411402115 is a deficient number, since it is larger than the sum of its proper divisors (6846841293).

11411402115 is an equidigital number, since it uses as much as digits as its factorization.

11411402115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 760760149.

The product of its (nonzero) digits is 160, while the sum is 21.

Adding to 11411402115 its reverse (51120411411), we get a palindrome (62531813526).

The spelling of 11411402115 in words is "eleven billion, four hundred eleven million, four hundred two thousand, one hundred fifteen".