11411442552441 has 4 divisors (see below), whose sum is σ = 15215256736592. Its totient is φ = 7607628368292.

The previous prime is 11411442552431. The next prime is 11411442552451. The reversal of 11411442552441 is 14425524411411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (11411442552431) and next prime (11411442552451).

It is not a de Polignac number, because 11411442552441 - 2¹¹ = 11411442550393 is a prime.

It is a super-3 number, since 3×11411442552441³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11411442552441.

It is not an unprimeable number, because it can be changed into a prime (11411442552431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1901907092071 + ... + 1901907092076.

It is an arithmetic number, because the mean of its divisors is an integer number (3803814184148).

Almost surely, 2^{11411442552441} is an apocalyptic number.

It is an amenable number.

11411442552441 is a deficient number, since it is larger than the sum of its proper divisors (3803814184151).

11411442552441 is an equidigital number, since it uses as much as digits as its factorization.

11411442552441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3803814184150.

The product of its digits is 102400, while the sum is 39.

Adding to 11411442552441 its reverse (14425524411411), we get a palindrome (25836966963852).

The spelling of 11411442552441 in words is "eleven trillion, four hundred eleven billion, four hundred forty-two million, five hundred fifty-two thousand, four hundred forty-one".