Base | Representation |
---|---|
bin | 11001111100101011011111… |
… | …000010110100100101010011 |
3 | 112222001212022022120122111022 |
4 | 121330223133002310211103 |
5 | 104424224323404113210 |
6 | 1042414250235110055 |
7 | 33015654224153513 |
oct | 3174533702644523 |
9 | 488055268518438 |
10 | 114121023113555 |
11 | 333a94aa467277 |
12 | 109715038a232b |
13 | 4b8a749224a93 |
14 | 20276b642d843 |
15 | d2d83a3bd155 |
hex | 67cadf0b4953 |
114121023113555 has 16 divisors (see below), whose sum is σ = 137341167206880. Its totient is φ = 91033103605248.
The previous prime is 114121023113497. The next prime is 114121023113567. The reversal of 114121023113555 is 555311320121411.
It is a cyclic number.
It is not a de Polignac number, because 114121023113555 - 210 = 114121023112531 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11566220 + ... + 19026809.
It is an arithmetic number, because the mean of its divisors is an integer number (8583822950430).
Almost surely, 2114121023113555 is an apocalyptic number.
114121023113555 is a deficient number, since it is larger than the sum of its proper divisors (23220144093325).
114121023113555 is a wasteful number, since it uses less digits than its factorization.
114121023113555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30595190.
The product of its (nonzero) digits is 18000, while the sum is 35.
Adding to 114121023113555 its reverse (555311320121411), we get a palindrome (669432343234966).
The spelling of 114121023113555 in words is "one hundred fourteen trillion, one hundred twenty-one billion, twenty-three million, one hundred thirteen thousand, five hundred fifty-five".
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