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114121023113555 = 5433172330593029
BaseRepresentation
bin11001111100101011011111…
…000010110100100101010011
3112222001212022022120122111022
4121330223133002310211103
5104424224323404113210
61042414250235110055
733015654224153513
oct3174533702644523
9488055268518438
10114121023113555
11333a94aa467277
12109715038a232b
134b8a749224a93
1420276b642d843
15d2d83a3bd155
hex67cadf0b4953

114121023113555 has 16 divisors (see below), whose sum is σ = 137341167206880. Its totient is φ = 91033103605248.

The previous prime is 114121023113497. The next prime is 114121023113567. The reversal of 114121023113555 is 555311320121411.

It is a cyclic number.

It is not a de Polignac number, because 114121023113555 - 210 = 114121023112531 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11566220 + ... + 19026809.

It is an arithmetic number, because the mean of its divisors is an integer number (8583822950430).

Almost surely, 2114121023113555 is an apocalyptic number.

114121023113555 is a deficient number, since it is larger than the sum of its proper divisors (23220144093325).

114121023113555 is a wasteful number, since it uses less digits than its factorization.

114121023113555 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30595190.

The product of its (nonzero) digits is 18000, while the sum is 35.

Adding to 114121023113555 its reverse (555311320121411), we get a palindrome (669432343234966).

The spelling of 114121023113555 in words is "one hundred fourteen trillion, one hundred twenty-one billion, twenty-three million, one hundred thirteen thousand, five hundred fifty-five".

Divisors: 1 5 433 1723 2165 8615 746059 3730295 30593029 152965145 13246781557 52711788967 66233907785 263558944835 22824204622711 114121023113555