Base | Representation |
---|---|
bin | 1010011000010010101010… |
… | …1100100100101111001001 |
3 | 1111102000111212121202121020 |
4 | 2212010222230210233021 |
5 | 2443440141233331403 |
6 | 40134445443103053 |
7 | 2255344004054205 |
oct | 246045254445711 |
9 | 44360455552536 |
10 | 11412444433353 |
11 | 36aaa993a7277 |
12 | 1343984671a89 |
13 | 64a25bcc4c12 |
14 | 2b65183a5b05 |
15 | 14bce5862453 |
hex | a612ab24bc9 |
11412444433353 has 8 divisors (see below), whose sum is σ = 15351252689568. Its totient is φ = 7540966233024.
The previous prime is 11412444433309. The next prime is 11412444433399. The reversal of 11412444433353 is 35333444421411.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11412444433353 - 218 = 11412444171209 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11412444433253) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16832513575 + ... + 16832514252.
It is an arithmetic number, because the mean of its divisors is an integer number (1918906586196).
Almost surely, 211412444433353 is an apocalyptic number.
It is an amenable number.
11412444433353 is a deficient number, since it is larger than the sum of its proper divisors (3938808256215).
11412444433353 is a wasteful number, since it uses less digits than its factorization.
11412444433353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33665027943.
The product of its digits is 829440, while the sum is 42.
Adding to 11412444433353 its reverse (35333444421411), we get a palindrome (46745888854764).
The spelling of 11412444433353 in words is "eleven trillion, four hundred twelve billion, four hundred forty-four million, four hundred thirty-three thousand, three hundred fifty-three".
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