Search a number
-
+
11412444433353 = 311333665027827
BaseRepresentation
bin1010011000010010101010…
…1100100100101111001001
31111102000111212121202121020
42212010222230210233021
52443440141233331403
640134445443103053
72255344004054205
oct246045254445711
944360455552536
1011412444433353
1136aaa993a7277
121343984671a89
1364a25bcc4c12
142b65183a5b05
1514bce5862453
hexa612ab24bc9

11412444433353 has 8 divisors (see below), whose sum is σ = 15351252689568. Its totient is φ = 7540966233024.

The previous prime is 11412444433309. The next prime is 11412444433399. The reversal of 11412444433353 is 35333444421411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11412444433353 - 218 = 11412444171209 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11412444433253) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16832513575 + ... + 16832514252.

It is an arithmetic number, because the mean of its divisors is an integer number (1918906586196).

Almost surely, 211412444433353 is an apocalyptic number.

It is an amenable number.

11412444433353 is a deficient number, since it is larger than the sum of its proper divisors (3938808256215).

11412444433353 is a wasteful number, since it uses less digits than its factorization.

11412444433353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33665027943.

The product of its digits is 829440, while the sum is 42.

Adding to 11412444433353 its reverse (35333444421411), we get a palindrome (46745888854764).

The spelling of 11412444433353 in words is "eleven trillion, four hundred twelve billion, four hundred forty-four million, four hundred thirty-three thousand, three hundred fifty-three".

Divisors: 1 3 113 339 33665027827 100995083481 3804148144451 11412444433353