Base | Representation |
---|---|
bin | 110101001001001011… |
… | …0100010100101000011 |
3 | 101220120112102220122211 |
4 | 1222102112202211003 |
5 | 3332211340011120 |
6 | 124232244442551 |
7 | 11150053342123 |
oct | 1522226424503 |
9 | 356515386584 |
10 | 114124532035 |
11 | 44444361078 |
12 | 1a1500a9457 |
13 | a9b9b712c7 |
14 | 5748cb2c83 |
15 | 2e7e26b25a |
hex | 1a925a2943 |
114124532035 has 4 divisors (see below), whose sum is σ = 136949438448. Its totient is φ = 91299625624.
The previous prime is 114124532029. The next prime is 114124532059. The reversal of 114124532035 is 530235421411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 114124532035 - 27 = 114124531907 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 114124531988 and 114124532006.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11412453199 + ... + 11412453208.
It is an arithmetic number, because the mean of its divisors is an integer number (34237359612).
Almost surely, 2114124532035 is an apocalyptic number.
114124532035 is a deficient number, since it is larger than the sum of its proper divisors (22824906413).
114124532035 is an equidigital number, since it uses as much as digits as its factorization.
114124532035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22824906412.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 114124532035 its reverse (530235421411), we get a palindrome (644359953446).
The spelling of 114124532035 in words is "one hundred fourteen billion, one hundred twenty-four million, five hundred thirty-two thousand, thirty-five".
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