Base | Representation |
---|---|
bin | 10101010000100010… |
… | …01011011001111011 |
3 | 1002110101120222111200 |
4 | 22220101023121323 |
5 | 141333212310133 |
6 | 5124300225243 |
7 | 552552661521 |
oct | 125021133173 |
9 | 32411528450 |
10 | 11413010043 |
11 | 492738a406 |
12 | 226623b223 |
13 | 10cb6728a6 |
14 | 7a3aa0311 |
15 | 46be72913 |
hex | 2a844b67b |
11413010043 has 6 divisors (see below), whose sum is σ = 16485458964. Its totient is φ = 7608673356.
The previous prime is 11413010039. The next prime is 11413010053. The reversal of 11413010043 is 34001031411.
11413010043 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11413010043 - 22 = 11413010039 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11413009998 and 11413010025.
It is not an unprimeable number, because it can be changed into a prime (11413010023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 634056105 + ... + 634056122.
It is an arithmetic number, because the mean of its divisors is an integer number (2747576494).
Almost surely, 211413010043 is an apocalyptic number.
11413010043 is a deficient number, since it is larger than the sum of its proper divisors (5072448921).
11413010043 is a wasteful number, since it uses less digits than its factorization.
11413010043 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1268112233 (or 1268112230 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 11413010043 its reverse (34001031411), we get a palindrome (45414041454).
The spelling of 11413010043 in words is "eleven billion, four hundred thirteen million, ten thousand, forty-three".
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