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1141302013201 = 7163043144743
BaseRepresentation
bin10000100110111010111…
…001101010110100010001
311001002220022002102120101
4100212322321222310101
5122144341303410301
62232150143012401
7145312346022130
oct20467271526421
94032808072511
101141302013201
114000292618a9
1216523789a101
138381681bc3c
143d34c95b917
151ea4b924701
hex109bae6ad11

1141302013201 has 4 divisors (see below), whose sum is σ = 1304345157952. Its totient is φ = 978258868452.

The previous prime is 1141302013151. The next prime is 1141302013211. The reversal of 1141302013201 is 1023102031411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1141302013201 - 213 = 1141302005009 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1141302013211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81521572365 + ... + 81521572378.

It is an arithmetic number, because the mean of its divisors is an integer number (326086289488).

Almost surely, 21141302013201 is an apocalyptic number.

It is an amenable number.

1141302013201 is a deficient number, since it is larger than the sum of its proper divisors (163043144751).

1141302013201 is an equidigital number, since it uses as much as digits as its factorization.

1141302013201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 163043144750.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 1141302013201 its reverse (1023102031411), we get a palindrome (2164404044612).

The spelling of 1141302013201 in words is "one trillion, one hundred forty-one billion, three hundred two million, thirteen thousand, two hundred one".

Divisors: 1 7 163043144743 1141302013201