Base | Representation |
---|---|
bin | 1010011000010100111001… |
… | …1000110110000000110011 |
3 | 1111102002001121101100021122 |
4 | 2212011032120312000303 |
5 | 2443442403032203021 |
6 | 40135025113412455 |
7 | 2255364564616136 |
oct | 246051630660063 |
9 | 44362047340248 |
10 | 11413043241011 |
11 | 3700276410335 |
12 | 1343b1110a12b |
13 | 64a326093b89 |
14 | 2b6573b1c21d |
15 | 14bd2d1e6bab |
hex | a614e636033 |
11413043241011 has 4 divisors (see below), whose sum is σ = 12013729727400. Its totient is φ = 10812356754624.
The previous prime is 11413043240999. The next prime is 11413043241013. The reversal of 11413043241011 is 11014234031411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11413043241011 - 210 = 11413043239987 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11413043241013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 300343243166 + ... + 300343243203.
It is an arithmetic number, because the mean of its divisors is an integer number (3003432431850).
Almost surely, 211413043241011 is an apocalyptic number.
11413043241011 is a deficient number, since it is larger than the sum of its proper divisors (600686486389).
11413043241011 is an equidigital number, since it uses as much as digits as its factorization.
11413043241011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 600686486388.
The product of its (nonzero) digits is 1152, while the sum is 26.
Adding to 11413043241011 its reverse (11014234031411), we get a palindrome (22427277272422).
The spelling of 11413043241011 in words is "eleven trillion, four hundred thirteen billion, forty-three million, two hundred forty-one thousand, eleven".
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