Base | Representation |
---|---|
bin | 10101010000100011… |
… | …00100110100010011 |
3 | 1002110101210021021210 |
4 | 22220101210310103 |
5 | 141333224123011 |
6 | 5124302351203 |
7 | 552553604136 |
oct | 125021446423 |
9 | 32411707253 |
10 | 11413114131 |
11 | 4927450631 |
12 | 226628b503 |
13 | 10cb6ab093 |
14 | 7a3aca21d |
15 | 46be936a6 |
hex | 2a8464d13 |
11413114131 has 4 divisors (see below), whose sum is σ = 15217485512. Its totient is φ = 7608742752.
The previous prime is 11413114127. The next prime is 11413114147. The reversal of 11413114131 is 13141131411.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 11413114131 - 22 = 11413114127 is a prime.
It is a super-2 number, since 2×114131141312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11413114098 and 11413114107.
It is not an unprimeable number, because it can be changed into a prime (11413114151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1902185686 + ... + 1902185691.
It is an arithmetic number, because the mean of its divisors is an integer number (3804371378).
Almost surely, 211413114131 is an apocalyptic number.
11413114131 is a deficient number, since it is larger than the sum of its proper divisors (3804371381).
11413114131 is an equidigital number, since it uses as much as digits as its factorization.
11413114131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3804371380.
The product of its digits is 144, while the sum is 21.
Adding to 11413114131 its reverse (13141131411), we get a palindrome (24554245542).
The spelling of 11413114131 in words is "eleven billion, four hundred thirteen million, one hundred fourteen thousand, one hundred thirty-one".
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