Base | Representation |
---|---|
bin | 1010011000010101010000… |
… | …1010000101111110110011 |
3 | 1111102002022100112010011211 |
4 | 2212011110022011332303 |
5 | 2443443102322200210 |
6 | 40135042452220551 |
7 | 2255400151436614 |
oct | 246052412057663 |
9 | 44362270463154 |
10 | 11413140037555 |
11 | 3700316013a83 |
12 | 1343b3960a757 |
13 | 64a340155539 |
14 | 2b6582917c0b |
15 | 14bd3696738a |
hex | a6154285fb3 |
11413140037555 has 8 divisors (see below), whose sum is σ = 13795737155712. Its totient is φ = 9063865956288.
The previous prime is 11413140037549. The next prime is 11413140037571. The reversal of 11413140037555 is 55573004131411.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11413140037555 - 219 = 11413139513267 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8330758467 + ... + 8330759836.
It is an arithmetic number, because the mean of its divisors is an integer number (1724467144464).
Almost surely, 211413140037555 is an apocalyptic number.
11413140037555 is a deficient number, since it is larger than the sum of its proper divisors (2382597118157).
11413140037555 is a wasteful number, since it uses less digits than its factorization.
11413140037555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16661518445.
The product of its (nonzero) digits is 126000, while the sum is 40.
Adding to 11413140037555 its reverse (55573004131411), we get a palindrome (66986144168966).
The spelling of 11413140037555 in words is "eleven trillion, four hundred thirteen billion, one hundred forty million, thirty-seven thousand, five hundred fifty-five".
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