Base | Representation |
---|---|
bin | 1010011000010110000001… |
… | …0000110110000110100001 |
3 | 1111102002211111200111021120 |
4 | 2212011200100312012201 |
5 | 2443444011320242423 |
6 | 40135114545242453 |
7 | 2255405165642064 |
oct | 246054020660641 |
9 | 44362744614246 |
10 | 11413343134113 |
11 | 370040a721478 |
12 | 1343b95633429 |
13 | 64a37325510b |
14 | 2b65a18a48db |
15 | 14bd496d3ee3 |
hex | a61604361a1 |
11413343134113 has 8 divisors (see below), whose sum is σ = 15226623000288. Its totient is φ = 7604479345344.
The previous prime is 11413343134051. The next prime is 11413343134157. The reversal of 11413343134113 is 31143134331411.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11413343134113 - 221 = 11413341036961 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11413343134013) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1104013320 + ... + 1104023657.
It is an arithmetic number, because the mean of its divisors is an integer number (1903327875036).
Almost surely, 211413343134113 is an apocalyptic number.
It is an amenable number.
11413343134113 is a deficient number, since it is larger than the sum of its proper divisors (3813279866175).
11413343134113 is a wasteful number, since it uses less digits than its factorization.
11413343134113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2208038703.
The product of its digits is 15552, while the sum is 33.
Adding to 11413343134113 its reverse (31143134331411), we get a palindrome (42556477465524).
The spelling of 11413343134113 in words is "eleven trillion, four hundred thirteen billion, three hundred forty-three million, one hundred thirty-four thousand, one hundred thirteen".
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