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1141344002011 = 7091609794079
BaseRepresentation
bin10000100110111101011…
…001110101111111011011
311001010000020002200101111
4100212331121311333123
5122144433031031021
62232154243001151
7145313365642363
oct20467531657733
94033006080344
101141344002011
1140004aa306a4
121652499691b7
1383822430aa5
143d35436b9a3
151ea5046a8e1
hex109bd675fdb

1141344002011 has 4 divisors (see below), whose sum is σ = 1142953796800. Its totient is φ = 1139734207224.

The previous prime is 1141344001999. The next prime is 1141344002021. The reversal of 1141344002011 is 1102004431411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1141344002011 - 25 = 1141344001979 is a prime.

It is a super-2 number, since 2×11413440020112 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1141344002021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 804896331 + ... + 804897748.

It is an arithmetic number, because the mean of its divisors is an integer number (285738449200).

Almost surely, 21141344002011 is an apocalyptic number.

1141344002011 is a deficient number, since it is larger than the sum of its proper divisors (1609794789).

1141344002011 is an equidigital number, since it uses as much as digits as its factorization.

1141344002011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1609794788.

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 1141344002011 its reverse (1102004431411), we get a palindrome (2243348433422).

The spelling of 1141344002011 in words is "one trillion, one hundred forty-one billion, three hundred forty-four million, two thousand, eleven".

Divisors: 1 709 1609794079 1141344002011