1141400113 has 4 divisors (see below), whose sum is σ = 1304457280. Its totient is φ = 978342948.

The previous prime is 1141400089. The next prime is 1141400171. The reversal of 1141400113 is 3110041411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3110041411 = 73 ⋅42603307.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1141400113 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1141400173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81528573 + ... + 81528586.

It is an arithmetic number, because the mean of its divisors is an integer number (326114320).

Almost surely, 2^1141400113 is an apocalyptic number.

It is an amenable number.

1141400113 is a deficient number, since it is larger than the sum of its proper divisors (163057167).

1141400113 is an equidigital number, since it uses as much as digits as its factorization.

1141400113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 163057166.

The product of its (nonzero) digits is 48, while the sum is 16.

The square root of 1141400113 is about 33784.6135541018. The cubic root of 1141400113 is about 1045.0714183922.

Adding to 1141400113 its reverse (3110041411), we get a palindrome (4251441524).

The spelling of 1141400113 in words is "one billion, one hundred forty-one million, four hundred thousand, one hundred thirteen".