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1141423315307 = 11103765755937
BaseRepresentation
bin10000100111000010001…
…000011001100101101011
311001010012202100012202222
4100213002020121211223
5122200113332042212
62232210154544255
7145315351045442
oct20470210314553
94033182305688
101141423315307
11400090782980
1216527043808b
13838359b0732
143d360ad5d59
151ea573d5c72
hex109c221996b

1141423315307 has 4 divisors (see below), whose sum is σ = 1245189071256. Its totient is φ = 1037657559360.

The previous prime is 1141423315271. The next prime is 1141423315313. The reversal of 1141423315307 is 7035133241411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1141423315307 - 212 = 1141423311211 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1141423315397) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51882877958 + ... + 51882877979.

It is an arithmetic number, because the mean of its divisors is an integer number (311297267814).

Almost surely, 21141423315307 is an apocalyptic number.

1141423315307 is a deficient number, since it is larger than the sum of its proper divisors (103765755949).

1141423315307 is a wasteful number, since it uses less digits than its factorization.

1141423315307 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 103765755948.

The product of its (nonzero) digits is 30240, while the sum is 35.

Adding to 1141423315307 its reverse (7035133241411), we get a palindrome (8176556556718).

The spelling of 1141423315307 in words is "one trillion, one hundred forty-one billion, four hundred twenty-three million, three hundred fifteen thousand, three hundred seven".

Divisors: 1 11 103765755937 1141423315307