Base | Representation |
---|---|
bin | 1010011000011001101100… |
… | …1101000111011000000001 |
3 | 1111102012101102102200202201 |
4 | 2212012123031013120001 |
5 | 2444003022443341113 |
6 | 40135401032313201 |
7 | 2255441534161066 |
oct | 246063315073001 |
9 | 44365342380681 |
10 | 11414332012033 |
11 | 3700877939055 |
12 | 1344210842801 |
13 | 64a4a0099a92 |
14 | 2b6656d58c6d |
15 | 14bda6419cdd |
hex | a619b347601 |
11414332012033 has 16 divisors (see below), whose sum is σ = 11996711600256. Its totient is φ = 10839246612480.
The previous prime is 11414332012001. The next prime is 11414332012051. The reversal of 11414332012033 is 33021023341411.
It is a cyclic number.
It is not a de Polignac number, because 11414332012033 - 25 = 11414332012001 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11414332011992 and 11414332012010.
It is not an unprimeable number, because it can be changed into a prime (11414332012333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2878785 + ... + 5578177.
It is an arithmetic number, because the mean of its divisors is an integer number (749794475016).
Almost surely, 211414332012033 is an apocalyptic number.
It is an amenable number.
11414332012033 is a deficient number, since it is larger than the sum of its proper divisors (582379588223).
11414332012033 is a wasteful number, since it uses less digits than its factorization.
11414332012033 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2700744.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 11414332012033 its reverse (33021023341411), we get a palindrome (44435355353444).
The spelling of 11414332012033 in words is "eleven trillion, four hundred fourteen billion, three hundred thirty-two million, twelve thousand, thirty-three".
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