11414353342131 has 6 divisors (see below), whose sum is σ = 16487399271980. Its totient is φ = 7609568894748.

The previous prime is 11414353342069. The next prime is 11414353342181. The reversal of 11414353342131 is 13124335341411.

11414353342131 is a `hidden beast` number, since 1 + 1 + 4 + 1 + 435 + 3 + 3 + 4 + 213 + 1 = 666.

It is not a de Polignac number, because 11414353342131 - 2¹⁵ = 11414353309363 is a prime.

It is a super-3 number, since 3×11414353342131³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11414353342181) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 634130741221 + ... + 634130741238.

Almost surely, 2^{11414353342131} is an apocalyptic number.

11414353342131 is a deficient number, since it is larger than the sum of its proper divisors (5073045929849).

11414353342131 is a wasteful number, since it uses less digits than its factorization.

11414353342131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1268261482465 (or 1268261482462 counting only the distinct ones).

The product of its digits is 51840, while the sum is 36.

Adding to 11414353342131 its reverse (13124335341411), we get a palindrome (24538688683542).

The spelling of 11414353342131 in words is "eleven trillion, four hundred fourteen billion, three hundred fifty-three million, three hundred forty-two thousand, one hundred thirty-one".