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11414433 = 33804811
BaseRepresentation
bin101011100010…
…101110100001
3210110220122210
4223202232201
510410230213
61044352333
7166010142
oct53425641
923426583
1011414433
116496918
1239a56a9
132498604
141731ac9
1510070c3
hexae2ba1

11414433 has 4 divisors (see below), whose sum is σ = 15219248. Its totient is φ = 7609620.

The previous prime is 11414419. The next prime is 11414453. The reversal of 11414433 is 33441411.

11414433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 11414433 - 26 = 11414369 is a prime.

It is a super-2 number, since 2×114144332 = 260578561422978, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11414453) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1902403 + ... + 1902408.

It is an arithmetic number, because the mean of its divisors is an integer number (3804812).

Almost surely, 211414433 is an apocalyptic number.

It is an amenable number.

11414433 is a deficient number, since it is larger than the sum of its proper divisors (3804815).

11414433 is an equidigital number, since it uses as much as digits as its factorization.

11414433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3804814.

The product of its digits is 576, while the sum is 21.

The square root of 11414433 is about 3378.5252699958. The cubic root of 11414433 is about 225.1566514034.

Adding to 11414433 its reverse (33441411), we get a palindrome (44855844).

The spelling of 11414433 in words is "eleven million, four hundred fourteen thousand, four hundred thirty-three".

Divisors: 1 3 3804811 11414433