11414540593 has 4 divisors (see below), whose sum is σ = 11414769520. Its totient is φ = 11414311668.

The previous prime is 11414540581. The next prime is 11414540611. The reversal of 11414540593 is 39504541411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11414540593 - 2⁵ = 11414540561 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11414340593) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4383 + ... + 151156.

It is an arithmetic number, because the mean of its divisors is an integer number (2853692380).

Almost surely, 2^11414540593 is an apocalyptic number.

It is an amenable number.

11414540593 is a deficient number, since it is larger than the sum of its proper divisors (228927).

11414540593 is an equidigital number, since it uses as much as digits as its factorization.

11414540593 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 228926.

The product of its (nonzero) digits is 43200, while the sum is 37.

The spelling of 11414540593 in words is "eleven billion, four hundred fourteen million, five hundred forty thousand, five hundred ninety-three".