11415041403531 has 8 divisors (see below), whose sum is σ = 15220088922000. Its totient is φ = 7610010743712.

The previous prime is 11415041403481. The next prime is 11415041403533. The reversal of 11415041403531 is 13530414051411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11415041403531 - 2¹¹ = 11415041401483 is a prime.

It is a super-3 number, since 3×11415041403531³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 11415041403492 and 11415041403501.

It is not an unprimeable number, because it can be changed into a prime (11415041403533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2539656 + ... + 5411093.

It is an arithmetic number, because the mean of its divisors is an integer number (1902511115250).

Almost surely, 2^{11415041403531} is an apocalyptic number.

11415041403531 is a deficient number, since it is larger than the sum of its proper divisors (3805047518469).

11415041403531 is an equidigital number, since it uses as much as digits as its factorization.

11415041403531 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8429325.

The product of its (nonzero) digits is 14400, while the sum is 33.

Adding to 11415041403531 its reverse (13530414051411), we get a palindrome (24945455454942).

The spelling of 11415041403531 in words is "eleven trillion, four hundred fifteen billion, forty-one million, four hundred three thousand, five hundred thirty-one".