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1142004434113 = 4521712525603
BaseRepresentation
bin10000100111100100110…
…001001100010011000001
311001011201020211002220201
4100213210301030103001
5122202311113342423
62232343554205201
7145335635345404
oct20474461142301
94034636732821
101142004434113
11400359805054
121653b2b83801
13838c91c820a
143d3b7d65d3b
151ea8d4242ad
hex109e4c4c4c1

1142004434113 has 4 divisors (see below), whose sum is σ = 1142007411888. Its totient is φ = 1142001456340.

The previous prime is 1142004434111. The next prime is 1142004434117. The reversal of 1142004434113 is 3114344002411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1142004434113 - 21 = 1142004434111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1142004434111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 810631 + ... + 1714972.

It is an arithmetic number, because the mean of its divisors is an integer number (285501852972).

Almost surely, 21142004434113 is an apocalyptic number.

It is an amenable number.

1142004434113 is a deficient number, since it is larger than the sum of its proper divisors (2977775).

1142004434113 is an equidigital number, since it uses as much as digits as its factorization.

1142004434113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2977774.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 1142004434113 its reverse (3114344002411), we get a palindrome (4256348436524).

The spelling of 1142004434113 in words is "one trillion, one hundred forty-two billion, four million, four hundred thirty-four thousand, one hundred thirteen".

Divisors: 1 452171 2525603 1142004434113