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1142013113 = 4014636151
BaseRepresentation
bin100010000010001…
…1011110010111001
32221120220021110222
41010010123302321
54314323404423
6305153145425
740204644203
oct10404336271
92846807428
101142013113
1153670039a
1227a55b275
131527a0907
14ab957773
156a3d43c8
hex4411bcb9

1142013113 has 8 divisors (see below), whose sum is σ = 1147520256. Its totient is φ = 1136520000.

The previous prime is 1142013079. The next prime is 1142013121. The reversal of 1142013113 is 3113102411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1142013113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1142013091 and 1142013100.

It is not an unprimeable number, because it can be changed into a prime (1142013163) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 182588 + ... + 188738.

It is an arithmetic number, because the mean of its divisors is an integer number (143440032).

Almost surely, 21142013113 is an apocalyptic number.

It is an amenable number.

1142013113 is a deficient number, since it is larger than the sum of its proper divisors (5507143).

1142013113 is an equidigital number, since it uses as much as digits as its factorization.

1142013113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7015.

The product of its (nonzero) digits is 72, while the sum is 17.

The square root of 1142013113 is about 33793.6845135300. The cubic root of 1142013113 is about 1045.2584734898.

Adding to 1142013113 its reverse (3113102411), we get a palindrome (4255115524).

The spelling of 1142013113 in words is "one billion, one hundred forty-two million, thirteen thousand, one hundred thirteen".

Divisors: 1 401 463 6151 185663 2466551 2847913 1142013113