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11420204403 = 33806734801
BaseRepresentation
bin10101010001011001…
…00111110101110011
31002110220010111022110
422220230213311303
5141342033020103
65125114340403
7553001064366
oct125054476563
932426114273
1011420204403
114930453663
12226872a703
1310cccc13ca
147a4a140dd
1546c8e4403
hex2a8b27d73

11420204403 has 4 divisors (see below), whose sum is σ = 15226939208. Its totient is φ = 7613469600.

The previous prime is 11420204381. The next prime is 11420204447. The reversal of 11420204403 is 30440202411.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 11420204403 - 26 = 11420204339 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11420204403.

It is not an unprimeable number, because it can be changed into a prime (11420204503) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1903367398 + ... + 1903367403.

It is an arithmetic number, because the mean of its divisors is an integer number (3806734802).

Almost surely, 211420204403 is an apocalyptic number.

11420204403 is a deficient number, since it is larger than the sum of its proper divisors (3806734805).

11420204403 is an equidigital number, since it uses as much as digits as its factorization.

11420204403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3806734804.

The product of its (nonzero) digits is 768, while the sum is 21.

Adding to 11420204403 its reverse (30440202411), we get a palindrome (41860406814).

The spelling of 11420204403 in words is "eleven billion, four hundred twenty million, two hundred four thousand, four hundred three".

Divisors: 1 3 3806734801 11420204403