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11420300113 = 19601068427
BaseRepresentation
bin10101010001011001…
…11111001101010001
31002110220022100121021
422220230333031101
5141342044100423
65125120355441
7553001643415
oct125054771521
932426270537
1011420300113
114930509562
122268775b81
131100025b41
147a4a3ad45
1546c91295d
hex2a8b3f351

11420300113 has 4 divisors (see below), whose sum is σ = 12021368560. Its totient is φ = 10819231668.

The previous prime is 11420300107. The next prime is 11420300117. The reversal of 11420300113 is 31100302411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31100302411 = 140269221719.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11420300113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11420300117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 300534195 + ... + 300534232.

It is an arithmetic number, because the mean of its divisors is an integer number (3005342140).

Almost surely, 211420300113 is an apocalyptic number.

It is an amenable number.

11420300113 is a deficient number, since it is larger than the sum of its proper divisors (601068447).

11420300113 is an equidigital number, since it uses as much as digits as its factorization.

11420300113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 601068446.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 11420300113 its reverse (31100302411), we get a palindrome (42520602524).

The spelling of 11420300113 in words is "eleven billion, four hundred twenty million, three hundred thousand, one hundred thirteen".

Divisors: 1 19 601068427 11420300113