Base | Representation |
---|---|
bin | 110101001011110010… |
… | …0010000010101011001 |
3 | 101220210122001102112102 |
4 | 1222113210100111121 |
5 | 3332401233412101 |
6 | 124245051453145 |
7 | 11152165044623 |
oct | 1522744202531 |
9 | 356718042472 |
10 | 114212013401 |
11 | 44489782122 |
12 | 1a1754571b5 |
13 | aa02020a25 |
14 | 5756765c13 |
15 | 2e86c9b86b |
hex | 1a97910559 |
114212013401 has 12 divisors (see below), whose sum is σ = 117495418320. Its totient is φ = 111018070800.
The previous prime is 114212013287. The next prime is 114212013413. The reversal of 114212013401 is 104310212411.
It is a de Polignac number, because none of the positive numbers 2k-114212013401 is a prime.
It is a super-2 number, since 2×1142120134012 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (114212013901) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1399130 + ... + 1478508.
It is an arithmetic number, because the mean of its divisors is an integer number (9791284860).
Almost surely, 2114212013401 is an apocalyptic number.
It is an amenable number.
114212013401 is a deficient number, since it is larger than the sum of its proper divisors (3283404919).
114212013401 is an equidigital number, since it uses as much as digits as its factorization.
114212013401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 80504 (or 80467 counting only the distinct ones).
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 114212013401 its reverse (104310212411), we get a palindrome (218522225812).
The spelling of 114212013401 in words is "one hundred fourteen billion, two hundred twelve million, thirteen thousand, four hundred one".
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